Y=-0.33x^2-12x

Solution for Y=-0.33x^2-12x equation:

=-0.33Y^2-12Y

We move all terms to the left:

-(-0.33Y^2-12Y)=0

We get rid of parentheses

0.33Y^2+12Y=0

a = 0.33; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·0.33·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*0.33}=\frac{-24}{0.66}
=-36+0.24/0.66
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*0.33}=\frac{0}{0.66}
=0
$